# How to tell if a date is between two other dates?

## Question or problem about Python programming:

I have the following codes:

```if date in (start, end):
print 'in between'
else:
print 'No!'
```

date, start and end are all variables with the format of 1/1. What should I do to have it print out the right result? i tried date as 10/2, start as 3/14 and end as 11/7 and it’s print ‘No!’, which means it’s not running right. I guess have to format them to a date format and then compare them.

## How to solve the problem:

### Solution 1:

As you are still not satisfied, I have another answer for you. Without using datetime and year.

It just uses built-in tuples and comparing them:

```d1 = (3, 28)
d2 = (3, 31)
d3 = (4, 2)
if d1 < d2 < d3:
print("BETWEEN!")
else:
print("NOT!")
```

You can create tuple like these easily:

```day = 16
month = 4
d = (month, day)
```

### Solution 2:

If you convert all your dates to `datetime.date`, you can write the following:

```if start <= date <= end:
print "in between"
else:
print "No!"
```

### Solution 3:

Use `datetime.date`:

http://docs.python.org/library/datetime.html#datetime.date

`<` operator is overloaded specially for you.

`date1 < date2` - date1 is considered less than date2 when date1 precedes date2 in time.

```>>> from datetime import date
>>> d1 = date(2011, 3, 28)
>>> d2 = date(2011, 3, 22)
>>> d3 = date(2011, 4, 3)
>>> d2 < d1 < d3
True
```

```from datetime import date

d1 = date(2011, 3, 28)
d2 = date(2011, 3, 22)
d3 = date(2011, 4, 3)

if d2 < d1 < d3:
print 'in between'
else:
print 'No!'
```

### Solution 4:

```from datetime import datetime

date_format = "%m/%d/%Y"

a = datetime.strptime('8/18/2008', date_format)

b = datetime.strptime('9/26/2007', date_format) # Date to be checked

c = datetime.strptime('9/25/2008', date_format)

d = datetime.strptime('8/18/2008', date_format)  #Date entered here should always be the same as 'a'

delta1 = b - a

delta2 = c - b

delta3 = d - a

if delta1.days >= delta3.days and delta2.days >= delta3.days:

print 'In between'

else:

print 'Not in between'
```