## Question or problem in the Swift programming language:

I declare the following:

var x:Int? var y:Int?

and I’d like a third variable z that contains the sum of x and y. Presumably, as x & y are optionals, z must also be an optional:

var z:Int? = x + y

but this gives a complier error “value of optional type ‘Int?’ not unwrapped; did you mean to use ‘!’ or ‘?'”

If I unwrap x & y:

var z:Int? = x! + y!

I get a run-time error as x & y are nil, so can’t be unwrapped.

I can achieve the desired result as follows:

var z:Int? if let x1 = x { if let y1 = y { z = x1+y1 } }

but this seems a bit verbose for adding together 2 integers! Is there a better way of achieving this?

## How to solve the problem:

### Solution 1:

Here is my take, I think it’s cleaner:

let none:Int? = nil let some:Int? = 2 func + (left: Int?, right:Int?) -> Int? { return left != nil ? right != nil ? left! + right! : left : right } println(none + none) println(none + some) println(some + none) println(some + some) println(2 + 2)

With results of:

nil Optional(2) Optional(2) Optional(4) 4

### Solution 2:

The best I can think of is:

if x && y { z = x! + y!; }

Since they are all Optionals… there’s really no way to avoid:

- checking that they aren’t
`nil`

- Unwrapping them before you add them.

### Solution 3:

Best solution IMO:

z = x.map { x in y.map { $0 + x } }

Did you know the map operator on `Optional<T>`

? It is very nice.

Documentation says:

If self == nil, returns nil. Otherwise, returns f(self!).

### Solution 4:

It depends exactly what you’re trying to achieve, but you could do it with an optional tuple:

var xy: (Int, Int)? var z: Int if let (x1, y1) = xy { z = x1 + y1 // Not executed } xy = (3, 4) if let (x1, y1) = xy { z = x1 + y1 // 7 }

**Update**

As @Jack Wu points out, this changes the semantics. If you were willing to be a bit more verbose, you could however do it as follows:

func optIntAdd(x: Int?, y: Int?) -> Int? { if let x1 = x { if let y1 = y { return x1 + y1 } } return nil } operator infix +! { } @infix func +! (x: Int?, y: Int?) -> Int?{ return optIntAdd(x, y) } var x: Int? var y: Int? var z: Int? z = x +! y // nil x = 1 z = x +! y // nil y = 2 z = x +! y // 3

Not sure “+!” is a useful choice of name for the operator, but it would’t let me choose “+?”.

### Solution 5:

z = (x ?? 0) + (y ?? 0)

*** Worked on Xcode 9 ***

### Solution 6:

Use optional chaining:

z = x? + y?