Why is Bool “AnyObject” instead of “Any”?

i0S Swift Issue

Question or problem in the Swift programming language:

I have a simple question: Why does Bool qualify as AnyObject
According to Apple’s documentation:

So why does this statement pass?

let bool = true
let explicitBool: Bool = true

if (bool is AnyObject){
    print("I'm an object")

if (explicitBool is AnyObject){
    print("I'm still an object!")

How to solve the problem:

Solution 1:

Because it’s being bridged to an NSNumber instance.

Swift automatically bridges certain native number types, such as Int
and Float, to NSNumber. – Using Swift with Cocoa and Objective-C (Swift 2.2) – Numbers

Try this:

let test = bool as AnyObject print(String(test.dynamicType)) 

Solution 2:

This behavior is due to the Playground runtime bridging to Objective-C/Cocoa APIs behind-the-scenes. Swift version 3.0-dev (LLVM 8fcf602916, Clang cf0a734990, Swift 000d413a62) on Linux does not reproduce this behavior, with or without Foundation imported

let someBool = true let someExplicitBool: Bool = true print(someBool.dynamicType) // Bool print(someExplicitBool.dynamicType) // Bool print(someBool is AnyObject) // false print(someExplicitBool is AnyObject) // fase 

Try it online.